18p^2-78p+80=0

Solution for 18p^2-78p+80=0 equation:

18p^2-78p+80=0

a = 18; b = -78; c = +80;
Δ = b2-4ac
Δ = -782-4·18·80
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-18}{2*18}=\frac{60}{36}
=1+2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+18}{2*18}=\frac{96}{36}
=2+2/3
$